abb inverter

Hi! You will be now verify about abb inverter product where you might discover the testimonials, videos, links and photographs which will certainly spark your interest. This web-site offer facts which you will want. There is a entire array of resources that are waiting to be found. You may also carry on reading and search much more evaluations or items as below. We’ve got thrilling resources that were gathered by our experts in abb inverter .hope you will get the top evaluations and obtain the appropriate solution about abb inverter .

Reviews: customer reviews...
List Price: unavailable
Sale Price: Too low to display.
Availability: unspecified

Product Description

No description available.


No features available.

There was an error connecting to the Amazon web service, or no results were found for your query.

Obviously, there is absolutely a complete lot further to understand about %keywords%. This brief write-up is just a begin, plus the next step is usually to do some additional analysis. In any case, the suggestions within the write-up set the stage for a a lot additional detailed therapy with the topic.

Fraf asked Logic gates and boolean algebra?

Hi. See pic: My textbook is silent on this one so I need help.

And got the following answer:

Ugh...I haven't done one of these in many years. Used to be good at it, though... The required expression is Y = AB(A+B). This uses AND and OR gates which according to the answers we aren't allowed to use. But what if we transform the whole thing using DeMorgan's law? Y = A' + B' + (A'B') Negating flips the values of all the variables, changes every AND to an OR and every OR to an AND. So count the operations, now. to get Y we need... a) An inverter to produce A' (a 2-input NAND or NOR gate can do this; just connect A to both inputs) b) An inverter to produce B' (again, a 2-input NAND or NOR can do this) c) A 3-input OR gate (they won't give us OR gates, but we can use a NOR gate and then invert the output with a NOR or NAND) d) An AND gate to produce the A'B'. (we can't have AND gates, but we can use a NAND and then invert the output with a NOR or NAND). So counting up elements from the above list, Y requires a) 1 (NAND or NOR) b) 1 (NAND or NOR) c) 1 NOR + 1 (NAND or NOR) d) 1 NAND + 1(NAND or NOR) Total:1 NOR, 1 NAND, 4 of whichever. So I believe (5) is correct; any combination of six gates with at least one NAND and at least one NOR is fine. (As mentioned above, this expression is stupidly easy if you simplify it. AB(A+B) = AAB + ABB = AB + AB = AB...but they aren't letting us do that.)

There was an error connecting to the Amazon web service, or no results were found for your query.

Tagged , , , , . Bookmark the permalink.

Comments are closed.