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Timmy asked how many solar panels will i need?

i am wanting to build a small tiny house running 3-4 12 volt 15 watt light bulbs for a lighting source and using a Koolatron Fun Kool 26 Quart 12V Portable Mini Fridge This cooler consumes 4.5 amps at 12 volts. The conversion is: 4.5 amps (X) times 12 volts (=) equals 54 watts. and i want a solar system that will have back up for 2 days with the lights on for probly 5-6 hours a day so theirs no room for error

And got the following answer:

Difficult to impossible to say. Your 'fridge' consumes 54 watts, and from that I assume it isn't a real compressor fridge but one of those car coolers that's running from a Peltier element, which in turn means that you can use it, at the most, to keep some drinks cool, but not to cool down any foodstuffs for conservation. The other problem with that calculation is that the power consumption of tat 'fridge' depeds (a lot!) on the outside temperature and how often you open it. But with those fridges, it's more or less safe to assume that you need them to run continously, so during 48 hours, you'll need 48 * 54 = 2592 Watt-hours. With the lamps, 4 * 15 watts * 2 * 6 hours = 720 Watt-hours, in total 3312 Watt-hours. This is what you need to get out of your battery. At 12 Volts, those 3312 Watt-hours correspond to 3312/12 = 276 Amp-hours. Since you should (if you want to do it more than once) only use about 70% of the rated battery capacity, this will mean you'll need a battery system of about 394 - make that 400 - Amp-hours at 12 Volts, equivalent to 4 really large car batteries (or 8 average car batteries). Next is the solar charging - you didn't say where you are or whether you'll need this setup the whole year through. But assuming moderate latitudes, all-year operation, good weather (i.e. never more than your stated 2 days cloudy or overcast) and optimum orientation of the panels, you'll need a solar panel setup with the capacity to recharge those batteries within less than 3 hours of full sunlight (which is what you'll get with fixed mounted panels on a good winter's day). SInce you have charging losses of about 20%, you'll need 3312 (Watt-hours) * 1.2 (charging losses) / 3 hours = 1325 Watts of peak panel power - and a fast charger, and fast chargeable batteries. How many panels that is depends on the panels - I've seen 12V panels in the range of 10...100 Watts, those will enable you to get away with a simple charge controller. Domestic panles for grid tie-in usually run around 200...300 Wats apiece, but you'll need an inverter (further losses) to use them to charge a 12 V system. In General, though, you'll need about 10 square meters (100 square feet) of panel area. If you really intend this seriously, and not just as a theoretical exercise, you'd do better to look at small boat/yacht suppliers. They have fridges that use a 'cold plate' to store the cold so you only need to run them once a day for a couple of hours. Also, 4*15 Watts is _a_lot_ if you're using LED lights - sufficient for bright light in a large room. Try to cut down that a bit. With a cold plate fridge and a single 15 watt (or 3*5 Watt) LED light, you might well come down from that 1.5 kW system to a single 150 Watt panel.

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