Do you want to know the most recent news about power bright inverters? Do you want to be the initial in line in regards to the developments on power bright inverters? Are you currently itching to get up to the minute details?
This artice will have the information which you will need that may be fresh in the supply! You are able to subscribe to our feeds or you’ll be able to join the mailing list, so you may make sure which you are in together with the occasions,and ahead of every person!
Reviews: customer reviews...
List Price: unavailable
Sale Price: Too low to display.
No description available.
No features available.
There was an error connecting to the Amazon web service, or no results were found for your query.
The subsequent time you know you occur to become acquiring the short end together with the stick, come back and spend us a take a look at. We would like to hear your comments regarding the post so please take a moment and drop us a line.
High excellent is our passion in conjunction with the reason we made our web-site. We want to spread the word about %keywords% to ensure that no one has to put up with mediocre and second incredibly greatest once more.
Fred asked How can I power a 40w light bulb with 9v?
I want to use a 9v battery and capacitors and whatever else i need to take a low current and make it pulse at a high one. How do I do this? I have capacitors/ resistors/ transistors/ just about everything I think i need. And I want the light to be pretty bright. Thanks
And got the following answer:
The lamp is operated by a specific voltage, maybe 120V. The power in watts is voltage times current in amps, so the current = 40W / 120V = 0.3333A. Thus we need 120V at a current of 0.3333A to light this lamp properly. It is possible to convert the 9V battery to 120V as required, but we still need to supply at least 40W from the source (battery). If there are no losses in the conversion, the current at 9V would be 40W / 9V = 4.444A. This current is too high, because most 9V batteries are too small to deliver it. A normal small 9V battery may only deliver 50mA, so 9V x 0.05A = 0.45W. Perhaps a battery made of 6 x D size Nicad cells would supply this current for a short time.. The conversion is made by using a transformer usually, so the transistors form an oscillator, chopping the DC from the battery into AC, which can be transformed, then the voltage can be stepped up using the transformer. This process could be 70% efficient, so there will be 1.4 times the power needed for the lamp drawn from the battery. It is possible to use capacitors to step up the voltage, by a process of repeatedly charging multiple capacitors connected across the battery, then changing the circuit using transistors as switches to switch all the capacitors in series. With no losses this would need 14 capacitors connected. This would be bulky, expensive and complex compared with the transformer method, so is not used for this type of conversion. Look up inverters for more information.