The best power bright inverters

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Fred asked How can I power a 40w light bulb with 9v?

I want to use a 9v battery and capacitors and whatever else i need to take a low current and make it pulse at a high one. How do I do this? I have capacitors/ resistors/ transistors/ just about everything I think i need. And I want the light to be pretty bright. Thanks

And got the following answer:

The lamp is operated by a specific voltage, maybe 120V. The power in watts is voltage times current in amps, so the current = 40W / 120V = 0.3333A. Thus we need 120V at a current of 0.3333A to light this lamp properly. It is possible to convert the 9V battery to 120V as required, but we still need to supply at least 40W from the source (battery). If there are no losses in the conversion, the current at 9V would be 40W / 9V = 4.444A. This current is too high, because most 9V batteries are too small to deliver it. A normal small 9V battery may only deliver 50mA, so 9V x 0.05A = 0.45W. Perhaps a battery made of 6 x D size Nicad cells would supply this current for a short time.. The conversion is made by using a transformer usually, so the transistors form an oscillator, chopping the DC from the battery into AC, which can be transformed, then the voltage can be stepped up using the transformer. This process could be 70% efficient, so there will be 1.4 times the power needed for the lamp drawn from the battery. It is possible to use capacitors to step up the voltage, by a process of repeatedly charging multiple capacitors connected across the battery, then changing the circuit using transistors as switches to switch all the capacitors in series. With no losses this would need 14 capacitors connected. This would be bulky, expensive and complex compared with the transformer method, so is not used for this type of conversion. Look up inverters for more information.

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